Question

Y=x^2+8x-2in a quadratic equation

Answer 1

Use the quadratic formula to find the values of x:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

In this case, a is 1, b is 8 and c is -2. Replace for these values and find the values of x.

`\begin{gathered} x=\frac{-8\pm\sqrt[]{64-4(1)(-2)}}{2(1)} \\ x=\frac{-8\pm\sqrt[]{64+8}}{2} \\ x=\frac{-8\pm6\sqrt[]{2}}{2} \\ x1=\frac{-8+6\sqrt[]{2}}{2}=-4+3\sqrt[]{2} \\ x2=\frac{-8-6\sqrt[]{2}}{2}=-4-3\sqrt[]{2} \end{gathered}`

The solutions are

`x=-4+3\sqrt[]{2};x=-4-3\sqrt[]{2}`