Question

Grade 12 calculus please help with question 3. i) ?image attached much appreciated

Answer 1

We have a height function

`h(t)=-16t²+96t+112`

Now, to find the average rate of change the height function on [1,3] seconds we have the following

`A_(\lbrack1,3\rbrack)=(h(3)-h(1))/(3-1)=(-16(3)^2+96(3)+112-(-16(1)^2+96(1)+112))/(3-1)=(-16(-8)+96(2))/(2)`

Then the average rate on [1,3] is given by

`A_(\lbrack1,3\rbrack)=(320)/(2)=160`

Then the average rate of change of the height function on the interval from 1 to 3 seconds is 160 meters