1 Answer

James McPherson · Answer 1 · 2023-07-16T02:20:37+0000

Answer

0.46 moles

Step-by-step explanation

Given:

Mass of iron (III) oxide sample = 74 g

What to find:

The amount (mole) of iron (III) oxide in a 74 g sample.

Solution:

The amount (mole) of iron (III) oxide in a 74 g sample can be calculated using the mole formula.

$Mole=\frac{Mass}{Molar\text{ }mass}$

Using the molar masses of Fe = 55.845 g/mol, and O = 15.999 g/mol.

The molar mass of Fe2O3 = (2 x 55.845) + (3 x 15.999) = 159.687 g/mol

Putting mass = 74 g and molar mass = 159.687 g/mol, the amount will be

$Mole=\frac{74\text{ }g}{159.687\text{ }g\text{/}mol}=0.463406539\text{ }mol$

Therefore, the amount of iron (III) oxide in a 74 g sample is approximately 0.46 moles.