Given the equations
![\begin{cases}5x+6y=18 \\ 2x-3y=12\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/college/8y50olehjahbmxqzfcka3tbaltg9rgwjxy.png)
First, she multiplied the second equation by 6:
![\begin{gathered} 6\cdot(2x-3y)=6\cdot12 \\ 6\cdot2x-6\cdot3y=6\cdot12 \\ 12x-18y=72 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jbog8orzlo5p0mxv1qg92dw1a5s9j4b238.png)
You have to determine the factor to multiply the equation 5x+6y=18 to be able to add both equations and eliminate one of the variables.
To do so, compare the coefficients of the like terms:
5x and 12x, "12" is not a multiple of 5, so there is no factor that when multiplied by 5x will give 12x as a product.
6y and 18y, 18 is a multiple of 6, if you multiply 6y by 3 the product will be 18y.
So, the factor you have to use to multiply the equation and eliminate one variable is 3.