Question

Two pools are being filled with water. To start, the first pool has 1900 liters of water and the second pool had 1372 liters of water. Water is being added to the first pool at a rate of 31 liters per minute. Water is being added to the second pool at a rate of 42 liters per minute.Let x be the number of minutes water has been added(a) For each pool, write an expression for the amount of water in the pool after x minutes.Amount of water in the first pool (in liters) = Amount of water in the second pool (in liters) =(b) Write an equation to show when the two pools would have the same amount of water.

Answer 1

For the first pool, we start with 1900 liters, and add water at a rate of 31 liters per minute, So the equation for the total amount of water in liters in terms of minutes is given by:

Water in Pool 1 = 1900 + 31 x

The other pool (Pool 2) starts with 1372 liters and the rate of water added is 42 liters per minutes, then after "x" minutes of being filled at this rate be have:

Water in Pool 2 = 1372 + 42 x

(b) For this part of the problem, when we assume that both amounts of water are the same, we equal the amount of water on each pool, connecting them via an equal sign:

Water in Pool 1 = Water in Pool 2

1900 + 31 x = 1372 + 42 x