ANSWER
![a)\text{ }57\degree](https://img.qammunity.org/2023/formulas/physics/college/ckzqxntrlaqz4vn6pgyobya9hkg6s3w9ih.png)
Step-by-step explanation
We want to find the angle at which the range for the projectiles will be the same.
The range for a projectile is given by:
![R=(u^2\sin2\theta)/(g)](https://img.qammunity.org/2023/formulas/mathematics/college/r443ga88w7ra3mbzhzibt16cbvhj8n2dny.png)
where u = initial velocity
θ = angle of the projectile
g = acceleration due to gravity
For a projectile to have the same range as one with an angle of 33° (given that other values are constant), the value of sin(2θ) must be equal for both projectiles.
Let us find the value of sin(2(33°)):
![\sin(2*33)=\sin66=0.9135](https://img.qammunity.org/2023/formulas/physics/college/1irkavcsm2uyhx0kfh6c0ztbd5gm7alj79.png)
Let us find the same for the angles in the options:
![\begin{gathered} \sin(2*57)=\sin114=0.9135 \\ \\ \sin(2*38)=\sin76=0.9703 \\ \\ \sin(2*45)=\sin90=1 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/thy2fq4bit2x602ly2v97r43ek1ho47die.png)
As we can see, the angle that will result in the same range as 33° is 57°.
The answer is option a.