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If the anglesarerepresented in degrees, find both angles:sin(2x + 3) = cos(2 +33)

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Answer

Angle 1 = 39°

Angle 2 = 51°

Step-by-step explanation

To solve this, we need to first express the relationship between sin and cos.

If Sin a = Cos b,

then, a + b = 90°

So for this question,

Sin (2x + 3) = Cos (x + 33)

From the explanation above, we know that

2x + 3° + x + 33° = 90°

2x + x + 3° + 33° = 90°

3x + 36° = 90°

3x = 90° - 36°

3x = 54°

Divide both sides by 3

(3x/3) = (54°/3)

x = 18°

So, we now find the two angles

Angle 1 = 2x + 3° = 2(18°) + 3° = 36° + 3° = 39°

Angle 2 = x + 33° = 18° + 33° = 51°

Hope this Helps!!!

User Mynetx
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