Answer:
Therefore, at x=0, -1, 1 , f(x) will be 0 . Hence, 0, -1 ,1 are the x-intercepts.
Plotting the graph on desmos, the graph will be as in the attachme
Explanation:
f(x)=x^4+x^3-x^2-x
=x^3(x+1)-x(x+1)
=(x+1)(x^3-x)
=(x+1)x(x^2-1)
=(x+1)x(x+1)(x-1)
=(x+1)2x(x-1)