Since the money is applied in an account that is compounded, we need to use the following expression:
![A=P\cdot(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/1hp3okcapx09i2vvtx1r7b88nlkj70kqsm.png)
Where A is the final amount, P is the initial amount, r is the interest rate, n is the number of times the value gets compounded in a year and t is the elapsed time.
![\begin{gathered} A=10000\cdot(1+(0.04)/(12))^(3\cdot12) \\ A=10000\cdot(1+0.0033)^(36)_{} \\ A=10000\cdot(1.0033)^(36) \\ A=10000\cdot1.1273 \\ A=11272.72 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/zlmrufnmbyi8wvvdyt1ksehtk4r4bcwy89.png)
She will have $11272.72 in 3 years.