Endpoint = (1,2)
distance = 5
Second endpoint
I think the answer is letter A, (6,7) let's check it
![\begin{gathered} \sqrt[]{(6-1)^2+(7-2)^2} \\ \sqrt[]{(5)^2+(5)^2} \\ \sqrt[]{25\text{ + 25}} \\ \sqrt[]{50} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pw4obu3lnitefwoa80inuvbcue7yl30ojw.png)
ok, but do you have a picture of this question?
please upload it
To graph (1, 2) when the two lines cross, count 1 unit to the right, and from that point, count two units up. right and up is for positive numbers.
You must count the fiirst number in the horizontal line, and the second number in the vertical line.
I'll try the point (6, -3) this point is not the answer
distance = squared root (6 - 1)^2 + (-3 - 2)^2
5^2 + 5^2
Point (-3, 1) this point is not the answer
(-3 - 1)^2 + (1 - 2)
16 - +1
(1, -3) This point is the answer
(1 - 1)^2 + (-3 - 2)