Let x be the number of cans of food, since we need more than or equal to 2000 cans, we can write
![x+668\ge2000](https://img.qammunity.org/2023/formulas/mathematics/high-school/fdm7iot929f8bj82qq47h6gvv4v0vlxdbu.png)
where 668 is the number of cans that they have been collected.
Now, we must find x. If we move 668 to the right hand side as -668, we get
![\begin{gathered} x\ge2000-668 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/txxb3u5fzmdkfh73nz7v1xeabbskvn3wj6.png)
which gives
![x\ge1332](https://img.qammunity.org/2023/formulas/mathematics/high-school/md7loris64dnssivsarhlw1br1h2b43ojs.png)
this means that they must collect more than or equalt to 1332 cans of food.