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Ruben Kazumov · Answer 1 · 2023-02-22T18:46:20+0000

The area of a trapezoid is the average of the bases multiplied by the height

$\begin{gathered} A=(a+b)/(2)\cdot h \\ \text{ Where} \\ a\colon\text{ long base} \\ b\colon\text{ short base} \\ h\colon\text{ height} \end{gathered}$

So, in this case, you have

$\begin{gathered} \\ a=16\operatorname{cm} \\ b=12\operatorname{cm} \\ h=8\operatorname{cm} \\ A=(a+b)/(2)\cdot h \\ A=\frac{16cm+12\operatorname{cm}}{2}\cdot8\operatorname{cm} \\ A=112\operatorname{cm}^2 \end{gathered}$

Therefore, the area of a trapezoid with these dimensions is 112 square centimeters.

Find the area of a trapezoid whose height is 8 cm and whose bases are 16 cm and 12 CM-example-1

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