Question

1 Jason is pulling a box across the room. He is pulling with a force of 29 newtons and his arm is making a 37 angle with the horizontal, what is the vertical component of the force he is pulling with?

2 One force of magnitude 41 acts on an object. Another force of magnitude 86 acts on the object at a right angle, what is the magnitude of the resultant force on the object?
3 Final grades are often computed using weighted averages. Some college professors use complicated weighted averages. Your college professor tells you he will give a 33%-67% split on grades between tests and homework where whichever average is higher will be the 67%. What will your final grade be if your homework average is 94 and your test average is 80?​

Answer 1

Question 1:

To find the vertical component in this scenario, you would use sine.

I would suggest using it on a calculator as it can become very time consuming on paper. Sine (angle) times force. Sin(30) times 19. I believe the answer is 9.5.

Question 2:

You would use Sine for vertical directions. I suggest doing it by calculator.

Sin(30) times 23 which would give you 11.5. sin(30) x 23. Then, you would subtract the weight of the box from it. so, 11.5 - 24. The net force is -12.5.

Question 3:

Use pythagoreans theorem √ x²+y² = ||V|| or a²+b² = c²

√68²+24² = √c²

Explanation: