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Use the grouping method to factor the polynomial below completely.

x3 4x² + 3x - 12
-
A. (x²+4)(x-3)
B. (x2-3)(x+4)
C. (x2-4) (x+3)
D. (x²+3)(x-4)
SUE

User Verax
by
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1 Answer

6 votes

Answer:

D. (x² + 3)(x - 4)

Explanation:

x³ - 4x² + 3x - 12

(x³ - 4x²) (3x - 12)

x²(x - 4) + 3(x - 4)

(x² + 3)(x - 4)

I hope this helps!

User Fooman
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