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There are 10 people in a math club. Three people will be chosen for the Pi Day committee. How many different ways can club members structurethe committee? A: 12B:604,800C: 720D: 120

User Sazary
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1 Answer

3 votes

We want to choose a committee of 3 people from a total number of 10 people. This is a case of combination. The formular for combination is expressed as

n!/k!(n - k)!

Where

n represents the total number of people that we want to choose from.

k represents the number of people that we want to choose.

n = 10

k = 3

Therefore, the number of ways would be

10!/3!(10 - 3)!

10!/3! * 7!

=

k

User Adam Chetnik
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