Answer:

Explanation:
Given the equation:

To solve the equation by completing the square, follow the steps below:
Step 1: Take the constant to the right-hand side.

Step 2: Divide the coefficient of x by 2, square it and add it to both sides.

Step 3: Write the left-hand side as a perfect square.

Step 4: Take the square root of both sides.

Step 5: Solve for x.
![\begin{gathered} x=-6\operatorname{\pm}√(42) \\ \implies x=-6+√(42),x=-6-√(42) \end{gathered}]()