Given
Laine - 3 hours
Leslie - 4 hours
Lance - 5 hours.
Let x be the amount of hours it would take when all three of them work together.
Add the sum of the rate of work and equate it to one over x
![\begin{gathered} (1)/(3)+(1)/(4)+(1)/(5)=(1)/(x) \\ (4\cdot5)/(60)+(3\cdot5)/(60)+(3\cdot4)/(60)=(1)/(x) \\ (20+15+12)/(60)=(1)/(x) \\ (47)/(60)=(1)/(x) \\ (60)/(47)=(x)/(1) \\ x=(60)/(47) \\ x\approx1.2766 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/9wy66fuh2yfv2m6w8hssl8s9bja7fl7q1w.png)
Rounding to one decimal place, the hours it takes is 1.3 hours.