We know that the interior angles of any triangle have to add 180°, we know angles AEC and angles EAC from triangle AEC, then we have that the next step is:
![m\angle ACE=63\text{ Sum of angles in triangle}](https://img.qammunity.org/2023/formulas/mathematics/college/qlxh2p9tbye0yvatug3iv42jzv5g9o1o8i.png)
Now, since line BE and EC are congruent this means that triangle BCE is isosceles, and then the next step would be:
![m\angle CBE=63\text{ Base angle of an isosceles triangle}](https://img.qammunity.org/2023/formulas/mathematics/college/7poh62fqytc4xff0mgis38f0nf4bhssdgg.png)
We notice that angles CBE and ABE form a linear pair, then we have:
![m\angle ABE=117\text{ Linear pair}](https://img.qammunity.org/2023/formulas/mathematics/college/iharme8x7oy4mvm9hv9uwiw8hwjzrcqz46.png)
Finally, once again we use the fact that the sum of interior angles is equal to 180°, then we have:
![m\angle AEB=22\text{ Sum of angles in triangle}](https://img.qammunity.org/2023/formulas/mathematics/college/2qvo05oa731356ipskdrt6iunnj0o5ra3z.png)