Question

P(A) = 0.48, P(B) = 0.42 and P(AandB) = 0.10.

P(B | A) =
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Answer 1

Given:

The probabilities of the event A and B are given as below

P(A) = 0.48, P(B) = 0.42 and

`P(A\cap B)=0.10`

Find:

we have to find the probability P(B|A).

Step-by-step explanation:

we know, the conditional probability

`P(B|A)=(P(A\cap B))/(P(A))`

Therefore, by using given values, we get

`P(B|A)=(P(A\cap B))/(P(A))=(0.10)/(0.48)=0.21`

Therefore, the probability P(B|A) = 0.21