Question

The velocity v of an object projected vertically upward with an initial The velocity v of an object projected vertically upward with an initial velocity of 64 feet per second is given by v=48-32twhere t is time in seconds. When does the object reach its maximum height?Someone please explain this

Answer 1

1.5 seconds

Step-by-step explanation:

The maximum height is reached when the velocity is zero. We know that the velocity of the object is given by v = 48 - 32t, so we need to solve the following equation:

v = 48 - 32t = 0

Solving for t, we get:

48 - 32t = 0

48 - 32t + 32t = 0 + 32t

48 = 32t

48/32 = 32t/32

1.5 = t

Therefore, the object reach its maximum height after 1.5 seconds