Question

In a parallel circuit with a 12 V battery and three 6 Ohm resistors, what is the total current through each single resistor? Select one:a.4 Ampsb.6 Ampsc.2 Ampsd.36 Amps

Answer 1

First, we need to find the total current. We can do this using ohm's law:

`\begin{gathered} I=(V)/(R) \\ where: \\ V=12V \\ (1)/(R)=(1)/(R1)+(1)/(R2)+(1)/(R3)=(1)/(6)+(1)/(6)+(1)/(6)=(1)/(2) \\ \\ R=2\Omega \end{gathered}`
`I=(12)/(2)=6A`

Now, the current through each resistor is given by:

`\begin{gathered} I_1=(I)/(3)=(6)/(3)=2A \\ or \\ I_1=(12)/(6)=2A \end{gathered}`

Answer:

c.

2 Amps