1 Answer

Si Zi · Answer 1 · 2023-10-09T01:48:33+0000

Solution:

A point-slope form for a line is given by the following equation:

where (x1,y1) is a point on the line, and m is a slope of this line. In this case, we have that:

(x1,y1)= (-2,3) and m = 2/3

so, the point-slope form for the given line would be:

$y-3_{}=(2)/(3)(x+2_{})$

so that, the correct answer is :

$y-3_{}=(2)/(3)(x+2_{})$

solving for y, this is equivalent to:

$y_{}=(2)/(3)(x+2_{})+3$

applying the distributive property, this is equivalent to:

$y\text{ = }(2)/(3)x+(4)/(3)+3$

or

$y\text{ = }(2)/(3)x+((4)/(3)+3)$

this is equivalent to

$y\text{ = }(2)/(3)x+(13)/(3)\text{ = }(2)/(3)x\text{ + 4.33}$

that is:

$y\text{ = }(2)/(3)x\text{ + 4.33}$

then, the y-intercept is 4.33

and the graph of this line is:

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