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Slove by substitution. Show work.9.) 2y=4x+6 y=2x+3

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Let:


\begin{gathered} 2y=4x+6_{\text{ }}(1) \\ y=2x+3_{\text{ }}(2) \\ \end{gathered}

Replace (2) into (1):


\begin{gathered} 2(2x+3)=4x+6 \\ 4x+6=4x+6 \\ 0=0 \end{gathered}

Therefore:

the system has infinitely many solutions

User Wilson Delgado
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