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if i have 17.9 moles of a gas at a pressure of 9.7 atm and a volume of 17 liters, what is the temperature

1 Answer

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Step-by-step explanation:

To answer this question, we will use the Clapeyron equation.

The Clapeyron equation is a mathematical expression proposed by the French physicist-chemist and civil engineer Benoit-Pierre-Émile Clapeyron and was formulated to describe the behavior of a perfect gas. Look at the following equation:

P.V = n.R.T

P = pressure generated by the gas on the walls of the container;

V = volume occupied by the gas and can be expressed in liters or cubic meters;

n = number of mol (amount of substance in the gas);

Obs.: The number of moles is expressed by the ratio between the mass of the gas (m) and its molar mass (M);

R = general gas constant proposed by Clapeyron and depends on the pressure unit used (in atm, it is 0.082; in mmHg, it is 62.3; in KPa, it is 8.31);

T = temperature at which the gas is subjected (always used in the unit Kelvin).

The question gives us:

n = 17.9 moles

P = 9.7 atm

V = 17 L

R = 0.082 atm.L/K.mol

T = ?

So:

9.7*17 = 17.9*0.082*T

T = 164.9/1.4678

T = 112.3 K

Answer: 112.3 K

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