In this question, we have a situation where a change in temperature and pressure occurs while the volume is kept constant, and in this situation, we have to use the Gay-Lussac's gas law formula to solve it, the formula is:
P1/T1 = P2/T2
Where:
P1 = initial pressure, 2.90 atm
T1 = initial Temperature in Kelvin, 123°C or 396 Kelvin
P2 = Final pressure, 0.18 atm
T2 = Final Temperature in Kelvin, ?
Now we add these values into the formula:
2.90/396 = 0.18/T2
0.0073 = 0.18/T2
T2 = 0.18/0.0073
T2 = 24.6 Kelvin of temperature, or -248 Celsius