We have that the scores of students on the SAT college entrance examination had a normal distribution with the following parameters:
![\begin{gathered} \mu=555.6 \\ \\ \sigma=25.4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/whw8kpmx1zjvaryf1ye2rmul04kt54wic9.png)
And we need to find the following information:
1. The probability that a student is randomly chosen from all those taking the test scores 559 or higher.
2. If we take a simple random sample of 30 students, we need to find:
• The mean of the sampling distribution
,
• The standard deviation of the sampling distribution
,
• The z-score that corresponds to the mean score x-hat = 559
,
• The probability that the mean score x-hat of these students is 559 or higher.
To find those answers, we can proceed as follows:
1. To find the probability that a student is randomly chosen from all those taking the test scores 559 or higher, we can find that probability by using the z-score associated with x = 559 as follows:
![\begin{gathered} z=(x-\mu)/(\sigma) \\ \\ z=(559-555.6)/(25.4)=0.133858267717\approx0.1339 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wdre9fxw7ojxkd1zroqn75me62p7nmlpjd.png)
And now, we can use the cumulative standard normal distribution table to find the cumulative probability for z = 0.1339. Then we have:
![P(z<0.1339)=0.553259174857](https://img.qammunity.org/2023/formulas/mathematics/college/g4g7v5yc7505y79r4uavtp1wsq6yxuavp3.png)
Since we need test scores of 559 or higher, then we have:
![\begin{gathered} P(z>0.1339)=1-P(z<0.1339)=0.446740825143\approx0.4467 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/p3u4yt36vaxdzj3ap9e8pu862dqxi9atae.png)
Therefore, the probability for test scores of 559 or higher is about 0.4467.