The system is conservative.
From the graph, the potential energy at the origin = 22 joules
Kinetic energy at the origin = 12 joules
Therefore,
![\begin{gathered} \text{ Kinetic energy + potential energy =22 + 12 = 34} \\ \text{This total will remain constant all through the graph} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/qjnedx2oaxyrg8byeqs3ryfvpjo94d3c8m.png)
The kinetic energy at 2.0m along the x-axis can be calculated as follows
let
x = kinetic energy at 2.0m
The potential energy at 2.0m = 10 joule
![\begin{gathered} 34=10+x \\ 34-10=x \\ x=24\text{ joules} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/u79ubo993y5moaqg6e1i4la3v3r9xfmysb.png)
Kinetic energy at 2.0m along the x-axis = 24 Joules