Given -
The first digit could be any number from 2 through 5
The second digit was either 3,4,5, or 6
The third digit could be any number except 1 or 7
To Find -
How many different area codes are possible =?
Step-by-Step Explanation -
There are 4 choices for the first number having numbers from 2 through 5: (2, 3, 4, 5)
There are 4 choices for the second number having numbers 3, 4, 5, or 6
There are 7 choices for the third number having numbers 0, 2, 3, 4, 6, 7, 8, 9 (except 1 or 7)
Now,
Different area codes possible = 4 × 4 × 7
Different area codes possible = 112
Final Answer -
Different area codes possible are = 112