Question

In a different plan for area codes, the first digit could be any number from 2 through 5, the second digit was either 3,4,5, or 6, and the third digit could be any number except 1 or 7. With this plan, how many different area codes are possible?

Answer 1

Given -

The first digit could be any number from 2 through 5

The second digit was either 3,4,5, or 6

The third digit could be any number except 1 or 7

To Find -

How many different area codes are possible =?

Step-by-Step Explanation -

There are 4 choices for the first number having numbers from 2 through 5: (2, 3, 4, 5)

There are 4 choices for the second number having numbers 3, 4, 5, or 6

There are 7 choices for the third number having numbers 0, 2, 3, 4, 6, 7, 8, 9 (except 1 or 7)

Now,

Different area codes possible = 4 × 4 × 7

Different area codes possible = 112

Final Answer -

Different area codes possible are = 112