x + 2y = 4
3x +2y = 8
Let's use the first equation to graph
x + 2y = 4
when x = 0
0 + 2y = 4
y = 2
when y = 0
x + 2(0) = 4
x = 4
Let's use the second equation to graph
3x + 2y = 8
when x = 0
3(0) + 2y = 8
2y = 8
y = 4
when y = 0
3x + 2(y) = 8
3x = 8
x = 8/3 = 2 2/3
The point of intersection is (2, 1)
Plug (2, 1) into the equations, we have:
x + 2y = 4
2 + 2(1) = 4
4 = 4
3x +2y = 8
3(2) + 2(1) = 8
6 + 2 = 8