Question

Find the mass of a sample of water if it’s temperature dropped 24.8 Degrees Celsius when it lost 870 J of heat. Water = 4.18 J/g degrees C Use the equation m=Q/(c* TRIANGLE T)

Answer 1

Mass of the sample of water = 8.39 g

Step-by-step explanation

Given:

Temperature change, ΔT = 24.8 °C

Heat lost, Q = 870 J

Specific heat of water, c = 4.18 J/g°C

What to find:

The mass of the sample of water.

Step-by-step solution:

Using

`m=(Q)/(c\Delta T)=\frac{870\text{ }J}{4.18\text{ }J\text{/}g°C*24.8°C}=\frac{870J}{103.664\text{ }J\text{/}g}=8.39\text{ }g`