Question

41. If mBAC = 304°, find mCAB.a. 28°c. 25°b. 56°D.50°

Answer 1

Given the figure below:

where

`m\angle BAC=304\degree`

To find m∠CAB,

Recall that angle at the center is twice the angle at the circumference.

Thus,

`\begin{gathered} Let\text{ }\angle COB=x \\ thus, \\ \angle CAB=(x)/(2) \end{gathered}`

Also,

`\begin{gathered} \angle BAC+\angle COB=360 \\ 304+x=360 \\ subtract\text{ 304 from both sides,} \\ 304-304+x=360-304 \\ \Rightarrow x=56 \end{gathered}`

Recall that

`\begin{gathered} \angle CAB=(x)/(2) \\ =(56)/(2) \\ \Rightarrow\angle CAB=28\degree \end{gathered}`

Hence, we have

`m\angle CAB=28\degree`

The correct option is A