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Write an equation in slope-intercept form for the line that passes through (-10,0) and is parallel to y=3x-16

User Albzi
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For two lines to be parallel, then their slopes are equal in value.

The equation given;


y=3x-16

Has its slope given as 3.

The slope of the line when given the equation is the coefficient of x.

Next step, we have a second line passing through the point (-10,0), and its slope is 3 (parallel to the first one given).

We have the following variables as;


(x,y)=(-10,0),m=3

The equation is slope-intercept form is;


y=mx+b

We can now substitute the values of, x, y and m and we would have;


\begin{gathered} y=mx+b \\ 0=3(-10)+b \\ 0=-30+b \\ \text{Add 30 to both sides and we'll have;} \\ 0+30=30-30+b \\ 30=b \end{gathered}

The value of b (the y-intercept) is 30.

The equation can now be properly written as;


\begin{gathered} y=mx+b \\ y=3x+30 \end{gathered}

ANSWER:


y=3x+30

User Starbolin
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