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Given r(x)= -5-x and s(x)=x²-8, which of the following is equivalent to t(x)=s(r(x)) a) t(x)= x²+10x+17 b) t(x)= -x²+3 c) t(x)= -x²-13 d) t(x)= x²-10x+3 e) None of the above
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Jan 23, 2023
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Given r(x)= -5-x and s(x)=x²-8, which of the following is equivalent to t(x)=s(r(x))
a) t(x)= x²+10x+17
b) t(x)= -x²+3
c) t(x)= -x²-13
d) t(x)= x²-10x+3
e) None of the above
Mathematics
college
Maroodb
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The answer would be s(r(x)) = -8 + (-8 + x² )²
Makdous
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Jan 24, 2023
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Makdous
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s(r(x)) = (-5-x)^2 -8
= 25 + 10x + x^2 - 8
= x^2 + 10x + 17
Mohammad Karimi
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Jan 29, 2023
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Mohammad Karimi
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