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Find the hight of a cone with the volume of 21 ft 3 and a radius of 4ft

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the formula is


\begin{gathered} V=(\pi* r^2* h)/(3) \\ \end{gathered}

then


\begin{gathered} 21=(\pi*4^2* h)/(3) \\ 21=(\pi*16* h)/(3) \\ 21=16.75h \\ (21)/(16.75)=(16.75h)/(16.75) \\ h=1.25 \end{gathered}

answer: 1.25 ft

User Manuel Allenspach
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