From the question, we are given that

We can then find the rate using the formula below.
![\begin{gathered} r=n\left[\left((A)/(P)\right)^{(1)/(nT)}-1\right] \\ r=12×\left[\left((25000)/(5000)\right)^{(1)/(12*10)}-1\right] \\ r=0.1620276 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fsda3jeaqsvc1bj19o1qtr2sf4bhjx5inv.png)
Therefore, we will convert to percentage.

The interest rate required to get a total amount of $25,000.00 from compound interest on a principal of $5,000.00 compounded 12 times per year over 10 years is
Answer: 16.203%