Question

Triangle JKL was 90 clockwise about the origin. Triangle J’K’L is graphed below . What were the coordinates of the pre-image point L?

Answer 1

The coordinates of the Preimage point L is;

`L=(2,4)`

Step-by-step explanation:

Given the image J'K'L';

with coordinates;

`\begin{gathered} J^(\prime)=(-2,-1) \\ K^(\prime)=(1,4) \\ L^(\prime)=(4,-2) \end{gathered}`

A 90 degree clockwise rotation can be represented by the rule;

`(x,y)\rightarrow(y,-x)`

Where;

(x,y) is the preimage

(y,-x) is the image.

So, the coordinates of the preimage point L can be solved as;

`\begin{gathered} L(x,y)\rightarrow L^(\prime)(4,-2) \\ x=-(-2) \\ x=2 \\ y=4 \\ So; \\ L=(2,4) \end{gathered}`

Therefore, the coordinates of the Preimage point L is;

`L=(2,4)`