Question

What is the period on Earth of a pendulum with a length of 1.0m?

Answer 1

Given:

the length of the pendulum is

`l=1\text{ m}`

Required: the period of the pendulum.

Step-by-step explanation:

the period of the pendulum of length l is given by

`T=2\pi\sqrt[2]{(l)/(g)}`

Plugging all the values in the above relation, we get

`\begin{gathered} T=2\pi\sqrt[\placeholder{⬚}]{\frac{1\text{ m}}{9.8\text{ m/s}^2}} \\ T=2*3.14*0.32 \\ T=2.0\text{ s} \end{gathered}`

Thus, the period of the pendulum is

`2\text{ s}`