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Factor Completely.x^4 - 16(x-2) (x-2) (x-2i) (x-2i)(x-2) (x+2) (x+2i) (x-2i)(x-2) (x+2) (x^2+4)(x^2-4) (x^2+4)

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The given expression is

x^4 - 16

This can be written as

x^4 - 4^2

(x^2)^2 - 4^2

According to the difference of two squares rule, A^2 - B^2 = (A + B)(A - B)

By applying this rule, it becomes

(x^2 - 4)(x^2 + 4)

We would simplify x^2 - 4

x^2 - 4 = x^2 - 2^2

Applying the difference of two squares rule, it becomes

(x - 2)(x + 2)

We would simplify x^2 + 4 = x^2 + 2^2

This would not give us real factors. Hence, it would result in complex numbers

A^2 + B^2 = A^2 - (- 1*B^2) = A^2 - (iB)^2 = (A + iB)(A - iB)

By applying this rule, it becomes

x^2 + 2^2 = (x + 2i)(x - 2i)

Therefore, the complete factorisation would be

(x - 2)(x + 2) (x + 2i)(x - 2i)

User Boyan Penev
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