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you order twelve burritos to go from a Mexican restaurant 5 with hot peppers and 7 without however the restaurant forgot to label them if you pick 3 burritos at random find the probability that exactly to have hot peppers

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The burritos with hot peppers is n(H) = 5.

The burritos without hot peppers is n(H') = 7.

Determine the propability for selected 3 burritos exactly 2 have hot peppers.


\begin{gathered} P(H)=(^5C_2\cdot^7C_1)/(^(12)C_3) \\ =(10\cdot7)/(220) \\ =(7)/(22) \end{gathered}

So, probability for selected 3 burritos, exactly two have hot peppers is 7/22.

User Poelinca Dorin
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