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2. The following table shows the probability of females and males preferring to drive an SUV or a sports car.(a) Are being male and preferring to drive a sports car independent or not independent? Show allcalculations to support your answer. Round answer to nearest hundredth. Be sure to answer thequestionLet A = being a maleLet B = preferring to drive a sports carAnswer:(b) Are being female and preferring to drive an SUV independent or not independent? Show allcalculations to support your answer. Round answer to nearest hundredth. Be sure to answer thequestionLet A = being a femaleLet B = preferring to drive an SUV

2. The following table shows the probability of females and males preferring to drive-example-1
User StinkyCat
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1 Answer

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Being a male and preferring to drive a sports car represents dependent events because being a male influence the event of preferring a sports car, according to the chart.

Hence, A and B are dependent events.

To demonstrate this, we have to use the following formula


P(A\cap B)=P(A)\cdot P(B)

Where,


\begin{gathered} P(A\cap B)=0.16 \\ P(A)=0.25 \\ P(B)=0.35 \end{gathered}

Then


\begin{gathered} 0.16=0.25\cdot0.35 \\ 0.16=0.0875 \end{gathered}

Given that this result is not true. We prove that the events are not independent.

Now, let's do the same process to answer (b).


P(A\cap B)=P(A)\cdot P(B)

Where


\begin{gathered} P(A)=0.75 \\ P(B)=0.65 \\ P(A\cap B)=0.56 \end{gathered}

Then


\begin{gathered} 0.56=0.75\cdot0.65 \\ 0.56=0.4875 \end{gathered}

Hence, A and B are dependent events.

User Adko
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