SOLUTION
Now, let us split the triangle in the picture into two as shown below
Now from the diagram above, we can see the two right-angle triangles.
From the smaller triangle NLY, to find the side LY, we will use the Pythagorean theorem. From the Pythagorean theorem

From here we have that
![\begin{gathered} |NL|^2=|NY|^2+|LY|^2 \\ 10^2=8^2+|LY|^2 \\ 100=64+|LY|^2 \\ |LY|^2=100-64 \\ |LY|^2=36 \\ \text{square root both sides } \\ \sqrt[]^2=\sqrt[]{36} \\ \text{square cancels square root, then } \\ |LY|=\sqrt[]{36} \\ |LY|=6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/u6fwi64m9wo53n9pk2zngodk5ede5a7yrd.png)
hence LY is 6
Also form the second triangle NMY, using Pythagoras theorem to find NM, we have that
![\begin{gathered} |NM|^2=|NY|^2+|MY|^2 \\ |NM|^2=8^2+15^2 \\ |NM|^2=64+225 \\ |NM|^2=289 \\ \sqrt[]^2=\sqrt[]{289} \\ |NM|=\sqrt[]{289} \\ |NM|=17 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/l65qnwhv4cnd58sd0ssedl355grua7e88g.png)
Hence, NM = 17
We will use the trig ratio SOHCAHTOA to find angle NMY. NMY is the marked angle in the second triangle. So so using the sides 8 (opposite) and 15(adjacent) we have

Hence angle NMY = 28.07 degrees
In the first triangle to find angle NLY, using the hypotenuse 10 and the opposite 8, we have

Hence angle NLY = 53.13 degrees