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Write the equation of the line that is parallel to - 8x-6y = 5 that passes through thepoint (-9, 1)

User Timo Reimann
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1 Answer

6 votes
6 votes

First,we will find the slope of the line

Using 8x - 6y = 5

we will have to re-arrange the equation above to be in the slope-intercept form.

That is; it should be in the form y = mx + b

8x - 6y = 5

6y = 8x -5

y = 8/6 x - 5/6

slope = 8/6 = 4/3

In a parellel equation the slope are the same, hence the slope of our new equation is 4/3

Next, we find the intercept of the new equation;

Using the point (-9, 1) and slope(m) = 4/3

we will substitute into the equation below and then solve for b, where b is the slope of our new equation

y = mx + b

1 = 4/3 (-9) + b

1 = 4(-3) + b

1 = - 12 + b

add 12 to both-side of the equation

1+ 12 = b

13 = b

b= 13

Substituting m = 4/3 and b = 13 into the formula; y = mx+ b

y = 4/3 x + 13


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User Ravthiru
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