Question

Calculate the force between charges 4 x 10^-8 C and 1.8 x 10^-6 C if they are 3.5 m apart.

Answer 1

`F=5.2824\cdot10^(-5)\text{ N}`

Step-by-step explanation

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.

`F=k(q_1\cdot q_2)/(r^2)`

where k is the coulomb constant

`k=8.9875\cdot10^9\text{ N }(m^2)/(C^2)`

Step 1

let

`\begin{gathered} q_1=4\cdot10^(-8)C \\ q_2=1.8\cdot10^(-6) \\ r=3.5\text{ m} \\ k=8.9875\cdot10^9\text{ N }(m^2)/(C^2) \end{gathered}`

now, replace.

`\begin{gathered} F=k(q_1\cdot q_2)/(r^2) \\ F=8.9875\cdot10^9\text{ N }(m^2)/(C^2)((4\cdot10^(-8)C\cdot1.8\cdot10^(-6))/((3.5m)^2)) \\ F=5.2824\cdot10^(-5)\text{ N} \end{gathered}`

I hope this helps you