Question

Find the cos equation given amplitude: 6, period: 2π, vertical shift: 0, and horizontal shift:OA. y = 6 cos 0 + 2OB. y = 6 cos 0 - 2OC. y = 6 cos (0+²)OD. y = 6 cos (0-3)Reset Selection2T3

Answer 1

Given: A cosine function with amplitude: 6, period: 2 pie, vertical shift: 0, and horizontal shift-

`(2\pi)/(3)`

Required: To determine the function.

Explanation: The cosine function is defined as-

`y=Acos(Bx-C)+D`

where

`\begin{gathered} A=Amplitude \\ (2\pi)/(B)=Period \\ (C)/(B)=Phase\text{ shift} \\ D=Verical\text{ shift} \end{gathered}`

Hence, the required function is-

`y=6cos(x-(2\pi)/(3))+0`

Final Answer: The function is-

`y=6cos(x-(2\pi)/(3))`

Hence, Option D is correct.