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What is y = -5/2 - 4 in standard form?

User Puemos
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1 Answer

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Answer:
y=(2)/(5)x\text{ + 2}Explanations:

The slope-intercept form of the equation of a line is:

y = mx + c

where m is the slope

and c is the y-intercept

The given equation is:


y\text{ = -}(5)/(2)x\text{ - 4}

Comparing the given equation with y = mx + c:

The slope, m = -5/2

The equation perpendicular to y = mx + c and passing through the point (x₁, y₁) is given by the equation:


\text{y - y}_1=(-1)/(m)(x-x_1)

Since m = -5/2

-1/m = 2/5

The line passes through the point (5, 4)

x₁ = 5, y₁ = 4

The equation becomes:


\begin{gathered} y\text{ - 4 = }(2)/(5)(x\text{ - 5)} \\ y\text{ - 4 = }(2)/(5)x\text{ - 2} \\ \text{y = }(2)/(5)x\text{ - 2 + 4} \\ y=(2)/(5)x\text{ + 2} \end{gathered}

User Hugomg
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