Question

Consider the rate law below.R=k[A][B]^2What effect does doubling the concentration of each reactant have on the rate?-The rate increases to two times the original rate.-The rate increases to four times the original rate.-The rate increases to six times the original rate.-The rate increases to eight times the original rate.

Answer 1

The rate increases to eight times the original rate.

Step-by-step explanation

When the concentration of each reaction is doubled, the rate increases by eighth compared to the initial rate.

Example: Rate =k[A][B]^2

Lets assume : [A]1 = 0.1 and [A]2 = 0.2

[B]1 = 0.2 and [B]2 = 0.4

Initially: Rate = (0.1)(0.2)^2 = 4x10^-3

After doubling: Rate = (0.2)(0.4)^2 = 0.032

Divide the final answer by the initial one

=> 0.032/4x10^-3 = 8