Question

Determine the temperature Kelvin of CO2(g) having a root mean square velocity of 4.37 * 10 ^ 2 m/s

Answer 1

The temperature is 336.9K.

Step-by-step explanation:

To calculate the temperature of CO2, it is necessary to replace the values of CO2 molar mass (0.044kg/mol), gas constant (R=8.314J/mol.K) and in this case the root mean square velocity (4.37x10^2m/s) in the root mean square velocity formula:

`\begin{gathered} V_(rms)=\sqrt{(3*R*T)/(m)} \\ 4.37*10^2(m)/(s)=\sqrt{(3*8.314(J)/(mol*K)*T)/(0.044(kg)/(mol))} \\ (4.37*10^2(m)/(s))^2=(3*8.314(J)/(mol*K)*T)/(0.044(kg)/(mol)) \\ 190,969(m^2)/(s^2)=566.86(J)/(kg*K)*T \\ (190,969(m^2)/(s^2))/(566.86(J)/(kg*K))=T \\ 336.9K=T \end{gathered}`

So, the temperature is 336.9K.