From the problem, we are given a point (8, -6) and an equation y = 4x + 7
The equation we are to obtain is perpendicular to y = 4x + 7
In Mathematical terms, it means the slope of the given equation and the one we are to find follow the relation:
![\begin{gathered} m_1\text{ = }\frac{-1}{m_2_{}_{}} \\ \text{where m}_{1\text{ }}\text{represents the slope of the first equation and }m_2\text{ represents the slope of the second equation} \end{gathered}]()
slope of the given equation = 4
![\text{Slope of the required equation = }(-1)/(4)\text{ = -0.25}](https://img.qammunity.org/2023/formulas/mathematics/college/cqak12p1i8yt0wg19oqkl62z78apsvum8o.png)
The required equation passes through a point (8,-6)
The formula for obtaining the equation with a given slope that passes through a point is given as :
![\text{ (y - y}_1)=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/college/9g7tklmfikeqqdrus5mkn8bm8cchai8v2v.png)
By substituting;
![\begin{gathered} (y\text{ - (-6)) = -0.25(x - 8)} \\ y\text{ + 6 = -0.25x + 2} \\ y\text{ = -0.25x -4} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pi5lw7ajja8kb8l2md7oiey9xiiylarp8p.png)
The equation in slope-intercept form is y = -0.25x - 4