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What is the equation, in slope-intercept form, of the line that passes throughthe point (8, -6) and is perpendicular to y = 4x+7?

User Dularie
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1 Answer

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From the problem, we are given a point (8, -6) and an equation y = 4x + 7

The equation we are to obtain is perpendicular to y = 4x + 7

In Mathematical terms, it means the slope of the given equation and the one we are to find follow the relation:


\begin{gathered} m_1\text{ = }\frac{-1}{m_2_{}_{}} \\ \text{where m}_{1\text{ }}\text{represents the slope of the first equation and }m_2\text{ represents the slope of the second equation} \end{gathered}

slope of the given equation = 4


\text{Slope of the required equation = }(-1)/(4)\text{ = -0.25}

The required equation passes through a point (8,-6)

The formula for obtaining the equation with a given slope that passes through a point is given as :


\text{ (y - y}_1)=m(x-x_1)

By substituting;


\begin{gathered} (y\text{ - (-6)) = -0.25(x - 8)} \\ y\text{ + 6 = -0.25x + 2} \\ y\text{ = -0.25x -4} \end{gathered}

The equation in slope-intercept form is y = -0.25x - 4

User Prithajnath
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