Given that the student's grades on three tests are 80, 81 and 70
Let the student's grade on the fourth test be X
In order to pass the course, the student must have an average of 80 or greater.
Hence,
![\begin{gathered} (80+81+70+X)/(4)\ge80 \\ (231+X)/(4)\ge80 \\ 231+X\ge320 \\ X\ge320-231 \\ X\ge89 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ba8jhlzapy2wlocsyp2g0k1m1h9mfl0ozy.png)
The score the student must get on the next test to get a B average or better is greater than or equal to 89