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In AJKL, JL is extended through point L to point M, mZJKL = - (3x – 16)º, mZLJK = (2x + 15), and mZKLM = (8x – 19)". Find mZLJK.

In AJKL, JL is extended through point L to point M, mZJKL = - (3x – 16)º, mZLJK = (2x-example-1

1 Answer

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Angle KLJ = 180 - (8x - 19)

Because all the inner angles of a triangle add 180 degrees, we can write:

(2x + 15) + (3x -16) + 180 - (8x - 19) = 180

Soving for x:

2x + 15 + 3x - 16 - 8x + 19 = 0

-3x + 18 = 0

-3x = -18

x = -18(-3) = 6

x = 6

Angle LJK:

2x + 15

2(6) + 15 = 12 + 15 = 27

Answer:

Angle LJK is 27 degrees

In AJKL, JL is extended through point L to point M, mZJKL = - (3x – 16)º, mZLJK = (2x-example-1
User Haider Ali Anjum
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